Introduction

In this lesson, you will learn how to find the equation of a line using two given points.

This video illustrates the lesson material below. Watching the video is optional.

• How to Find the Equation of a Line from Two Points (7:13 mins) | Transcript

How to Find the Equation of a Line From Two Points

Here are two points: $(-5,13)$ and $(3,-3)$. Both of these points are on the same line (see Figure 1). To find the equation of this line, follow three steps:

Figure 1

Step 1
Find the slope using the slope formula: $m=\frac{y_{2-}{y}_1}{x_{2-}{x}_1}$

$$\begin{array}{rlr}m& =\frac{y_2-y_1}{x_2-x_1}& \text{Slope formula}\\ \\ m& =\frac{13-(-3)}{-5-3}& \text{Substitute values of x \& y}\\ \\ m& =\frac{16}{-8}& \text{Simplify numerator and denominator}\\ \\ m& =-2& \text{Simplify the fraction}\\ \end{array}$$

The slope is -2 for this equation.

Figure 2

Step 2
Use the slope and one of the points to solve for the y-intercept using the slope-intercept form: $y=mx+b$. It does not matter which point you use to find the equation. Here, $(3,-3)$ is used with $m=-2$.

$$\begin{array}{rlr}y& =mx+b& \text{Slope-intercept form}\\ \\ -3& =-2(3)+b& \text{Substitute values of m, x, \& y}\\ \\ -3& =-6+b& \text{Right side: multiply -2 \& 3}\\ \\ -3\text{+6}& =-6+b\text{+6}& \text{Add 6 to both sides}\\ \\ -3\text{+6}& =b& \text{Right side: the 6's will cancel}\\ \\ 3& =b& \text{Left side: subtract 3 from 6}\end{array}$$

The y-intercept, or b, is equal to 3.

Step 3
Once you know the value for m and the value for b, you can substitute these into the slope-intercept form to get the equation for the line. The equation of the line that both of these points go through is $y=-2x+3$.

Things to Remember

• The slope formula is $m=\frac{y_{2-}{y}_1}{x_{2-}{x}_1}$.
• The steps to find the equation of a line, when given two points are:
  
  1. Find the slope using the slope formula.
  2. Use the slope and one of the points given to solve for the y-intercept in the slope-intercept form of a line: $y=mx+b$.
  3. Use the slope (m) and y-intercept (b) to write the equation of the line using the slope-intercept form.

Practice Problems

1. $\text{Extra left or missing right}$ and $\text{Extra left or missing right}$ (
   Solution

   x

   Solution: $\text{y}=-3\text{x}-5$
   
   Details:
   
   Step 1: Find the slope using the formula:
   
   ${\displaystyle \text{Slope}=\text{m}=\frac{\text{rise}}{\text{run}}=\frac{{\text{y}}_2-{\text{y}}_1}{{\text{x}}_2-{\text{x}}_1}}$
   
   You have two points,$(-5,10)$ and $(-3,4)$. For this example, choose $(-5,10)$ as point one and $(-3,4)$ as point two. (It does not matter which is point one and which is point two as long as you stay consistent throughout the calculations.) Input the points into the formula for slope:
   
   ${\displaystyle \frac{{\text{y}}_2-{\text{y}}_1}{{\text{x}}_2-{\text{x}}_1}=\frac{4-10}{-3-(-5)}}$
   
   Simplify:
   
   ${\displaystyle \frac{4-10}{-3-(-5)}}={\displaystyle \frac{4-10}{-3+5}}={\displaystyle \frac{-6}{2}}=-3$
   
   The slope of the line is $-3$, so the m in $y=mx+b$ is $-3$.
   
   Step 2: Use the slope and one of the points to find the y-intercept b:
   
   It doesn’t matter which point you use. They will both give you the same value for b since they are on the same line. In this example, choose the point $(-3,4)$. Input the slope, $-3$, and the point into $y=mx+b$ to get the equation of the line:
   
   $4=-3\left(-3\right)+\text{b}$
   
   Simplify:
   
   $4=9+b$
   
   Then subtract 9 from both sides:
   
   $4-9=9+b-9$
   
   $-5=\text{b}$
   
   Step 3: Input the slope (m = $-3$), and the y-intercept (b = $-5$), into $y=mx+b$:
   
   $\text{y}=-3\text{x}-5$
   )
2. $\text{Extra left or missing right}$ and $\text{Extra left or missing right}$ (
   Solution

   x

   Solution: $\text{y}=6\text{x}+4$
   )
3. $\text{Extra left or missing right}$ and $\text{Extra left or missing right}$ (
   Solution

   x

   Solution: $\text{y}=6\text{x}+2$
   
   Details:
   
   Step 1: Find the slope using the formula:
   
   ${\displaystyle \text{Slope}=\text{m}=\frac{\text{rise}}{\text{run}}=\frac{{\text{y}}_2-{\text{y}}_1}{{\text{x}}_2-{\text{x}}_1}}$
   
   You have two points, $(-4,-22)$ and $(-6,-34)$. In this example, choose $(-4,-22)$ as point one and $(-6,-34)$ as point two. (It does not matter which is point one and which is point two as long as you stay consistent throughout the calculations.) Input the points into the formula for slope:
   
   ${\displaystyle \frac{{\text{y}}_2-{\text{y}}_1}{{\text{x}}_2-{\text{x}}_1}=\frac{-34-(-22)}{-6-(-4)}}$
   
   Simplify:
   
   ${\displaystyle \frac{-34-(-22)}{-6-(-4)}}={\displaystyle \frac{-34+22}{-6+4}}={\displaystyle \frac{-12}{-2}}=6$
   
   So the slope of the line is 6.
   
   Step 2: Use the slope and one of the points to find b.
   
   It doesn’t matter which point you use. They will both give you the same value for b since they are on the same line. In this example, choose the point $(-4,-22)$. Input the slope, 6, and the point into $y=mx+b$ to get the equation of the line.
   
   $-22=6(-4)+\text{b}$
   
   Simplify:
   
   $-22=-24+\text{b}$
   
   Then add 24 to both sides.
   
   $-22+24=-24+\text{b}+24$
   
   $2=b$
   
   Step 3: Plug the slope $m=6$, and the y-intercept $b=2$, into $y=mx+b$.
   
   $y=6x+2$
   )
4. $\text{Extra left or missing right}$ and $\text{Extra left or missing right}$ (
   Solution

   x

   Solution: $\text{y}={\displaystyle \frac{1}{3}}\text{x}$
   )
5. $\text{Extra left or missing right}$ and $\text{Extra left or missing right}$ (
   Solution

   x

   Solution: $\text{y}={\displaystyle \frac{9}{2}}\text{x}-24$
   )
6. $\text{Extra left or missing right}$ and $\text{Extra left or missing right}$ (
   Solution

   x

   Solution: $\text{y}={\displaystyle \frac{3}{2}}\text{x}-{\displaystyle \frac{5}{2}}$
   )